Question

x²-2/p(p²+1)+4
What is the value of factor

Answer 1

p=2 or p=−1

Explanation:

The roots of a quadratic ax2+bx+c=0 are equal when the discriminant (b2−4ac) is equal to 0

In this case

a=1

b=−2p

c=(p+2)

So the discriminant is

(-2p)2−4(1)(p+2) =4p2−4p−8

which factors as

=4(p−2) (p+1)

and the discriminant

=0 if p=2 or p=−1