Hi there!
We can begin by converting 130 km/h to m/s:
[tex]\frac{130km}{1hr} * \frac{1hr}{3600s} * \frac{1000m}{1km} = 36.11 m/s[/tex]
Find the acceleration associated with this velocity change in the given time frame:
vf = vi + at (vi = 0 m/s)
vf = at
vf/t = a
36.11/80 = 0.45 m/s²
Now, we can calculate Net Force using Newton's Second Law:
∑F = ma
∑F = (1200)(0.45) ≈ 540 N