Question

7. A taxi is travelling at 15 m/s. Its driver accelerates with acceleration 3 m/s2 for 4 s. What is its new velocity​

Answer 1

Hi there!

To solve, we can use the following equation:

vf = vi + at

vi = initial velocity (m/s)

a = acceleration (m/s²)

t = time (s)

vf = final velocity (m/s)

Plug in the given values:

vf = 15 + 3(4)

vf = 15 + 12 = 27 m/s

Answer 2

Answer:

$\boxed {\boxed {\sf 27 \ m/s}}$

Explanation:

We are asked to find the new or final velocity of a taxi.

We will use the following kinematic equation:

$v_f=v_i+at$

The car was initially traveling at 15 meters per second. It accelerated at 3 meters per second squared for 4 seconds.

• $v_i=$15 m/s
• $a=$3 m/s ²
• t= 4 s

Substitute the values into the formula.

$v_f= 15 \ m/s + (3 \ m/s^2* 4 \ s)$

Multiply the numbers in parentheses.

• 3 m/s/s * 4 s = 3 m/s *4 = 12 m/s

$v_f= 15 \ m/s +12 \ m/s$

Add.

$v_f=27 \ m/s$

The new velocity of the taxi is 27 meters per second.