Question

Quadrilateral BCHS is a parallelogram with diagonal BH

intersecting diagonal CS at P.

angle BCH = 3x-3.86

angle CHS = 2x+6.58

Find the measure of angle HSB

Answer 1

Answer:

Step-by-step explanation:

HSB will equal BCH

The four internal angles of a parallelogram sum to 360°

Opposite internal angles are equal.

2(3x - 3.86) + 2(2x + 6.58) = 360

6x - 7.72 + 4x + 13.16 = 360

10x = 354.56

x = 35.456

HSB = (3(35.456) - 3.86) = 102.508°