The time the boat is 0.5 m above the mean position during each cycle is (4n + 0.375) s
Since y = f(x) = 0.9sin(πx/2)
We want to determine the time, x at which the boat is 0.5 m above its mean position. This is the value of y at y = 0.5 m
So, y = f(x) = 0.9sin(πx/2)
0.5 = 0.9sin(πx/2)
Dividing through by 0.9, we have
0.5/0.9 = sin(πx/2)
5/9 = sin(πx/2)
Taking inverse sine of both sides, we have
sin⁻¹(5/9) = πx/2
sin⁻¹(0.5556) = πx/2
0.589 rad = πx/2
x = 2 × 0.589/π
x = 1.178/π
x = 0.375 s
Since the boat repeats its cycle every 4 seconds, the time the boat is 0.5 m above the mean position after n cycles is t = (4n + 0.375) swhere n is a positive integer. That is n = 0, 1, 2, 3...
So, the time the boat is 0.5 m above the mean position during each cycle is (4n + 0.375) s
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