This question is asking for the complete, ionic and net ionic chemical equations for the reaction between liquid bromine with a solution of hydrochloric acid and cobalt (II) iodate mixed with a solution of iron (III) oxalate.
In this case, according to the given information, it turns out possible to figure out the required, by considering that the complete chemical equation has the correct balance and states of all species involved, the ionic one shows the ionizable species and the net ionic do not show any spectator ion. In such a way, we proceed as follows:
a.
[tex]Br_2(l)+2HCl(aq)\rightarrow Cl_2(g)+2HBr(aq)[/tex]: Complete.
We can ionize HCl and HBr as they are aqueous:
[tex]Br_2(l)+2H^+(aq)+2Cl^-(aq)\rightarrow Cl_2(g)+2H^+(aq)+2Br^-(aq)[/tex]: Ionic
Finally, we cancel out the hydrogen ions as the spectator ones:[tex]Br_2(l)+2Cl^-(aq)\rightarrow Cl_2(g)+2Br^-(aq)[/tex]
b.
[tex]3Co(IO_3)_2(s)+Fe_2(C_2O_4)_3(aq)\rightarrow 3CoC_2O_4(s)+2Fe(IO_3)_3(aq)[/tex]: Complete
We ionize the iron-containing species:
[tex]3Co(IO_3)_2(s)+2Fe^{3+}(aq)+3(C_2O_4)^{2-}(aq)\rightarrow 3CoC_2O_4(s)++2Fe^{3+}(aq)+6(IO_3)^-(aq)[/tex]
Finally, we cancel out the iron ions as the spectator ones:
[tex]3Co(IO_3)_2(s)+3(C_2O_4)^{2-}(aq)\rightarrow 3CoC_2O_4(s)+(aq)+6(IO_3)^-(aq)[/tex]
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