Question

Simplify: $-\sqrt{16x^2}$ if x<0

Answer 1

Answer:

$-4x$

Step-by-step explanation:

First, let us write this equation into an easier one. We have:

$-\sqrt{16x^2}=-\sqrt{4^2x^2}$

The exponents cancel out with the square root, so we have:

$-4x$

as our answer.

HOPE IT HELPS :D