Answer:
10s
Explanation:
Classic accelerated motion question. The formula giving us the distance traveled given intial speed and time taken is:
[tex]\Delta x = v_0\Delta t +\frac12 a (\Delta t)^2[/tex]
We know the acceleration, we know the initial speed (it was at rest, so it's zero), let's replace and solve:
[tex]400 = 0 \Delta t + \frac 12 (0.5) (\Delta t)^2 \rightarrow 100 = (\Delta t)^2\\\Delta t = 10s[/tex]