Question

list all the possible rational zeros of p(x)=3x^3-3x^2+4x-12

Answer 1

Answer:

$x = 3$

$x)=x^3-3x^2-4x+12 \\ 0 = 3x ^2 - 3x ^2 + 4x - 12 \\ 0 = 4x - 12 \\ - 4x = - 12 \\ - x = - 12 \div 4 \\ x = 3$