Question

What is an equation of the line that passes through the points (-3, 3) and (-6, 2)?

Answer 1

Answer:

3y=3x+ c

Step-by-step explanation:

-3= x1 and 3 = y1

-6= x2 and 2= y2

y2-y1/ x2-x1 = 2-3/ -6+3 = -1/-3 =1/3 (the gradient)

y =1/3x +c

multiplying both sides by 3

3y= 3x +c in the form of y= mx + c

Answer 2

First of all In an equation you need slope and y-intercept according to the rule Y=Mx+c

M= y2-y1/x2-x1 = 2-3/-6-(-3) = -1/-3 = 1/3

Y= 1/3x+c

(NOW WE HAVE THE SLOPE AND WE CAN FIND THE Y-INTERCEPT BY REPLACING IN ONE OF THE GIVING POINTS)

3= 1/3(-3)+c

C=4

Final answer is y = 1/3x + 4