Question

Find there consecutive even integers such that the sum of smallest number and twice the middle number is 20 more then the largest number

Answer 1

Answer:

The numbers are 10, 12, and 14

Step-by-step explanation:

x + 2(x+2) = x+4 + 20

x = 10

So the numbers are 10,12,14

Answer 2

Here is your answer

let the numbers be x,x+2,x+4

so,the equation is

x+2(x+2)=x+4+20

3x+4=x+24

2x=20

x=10

therefore the nos. are 10,12,14

Hope This Helps