Question

the smallest plus the largest of three consecutive odd integers is twelve less than six times the middle integer. find the smallest integer

Answer 1

Answer:

1

Step-by-step explanation:

let x = smallest

let x+2 = middle

let x+4 = largest

x + x + 4 = 6(x +2) - 12

2x + 4 = 6x + 12 - 12

2x + 4 = 6x

4 = 4x

x = 1

numbers are 1, 3, 5

check:

is 1 + 5 equal to 6(3) - 12

6 = 18 - 12

6 = 6