The only part of the diagram that remains is the force that moves the object forward which is 50 N.
We know that the net force is obtained using the relation;
Net force = -Frictional force + Rightward force
The frictional force is negative because its direction is opposite to that of the forward force.
We have the following information from the question;
Frictional force = 30 N
Rightward force = 80 N
Mass = 5.00 kg
Net force is obtained from;
5a = 80 - 30
5a = 50
a = 10 m/s^2
Net force = 50 N, This the force that moves the object forward.
Learn more: https://brainly.com/question/11324711
