50 points and brainliest to first correct answer :)

Theorem: A line parallel to one side of a triangle divides the other two proportionately.
In the figure below, segment DE is parallel to segment BC and segment EF is parallel to AB:


The figure shows triangle ABC with segments DE and DF. Point D is on side AB, point E is on side AC, and point F is on side BC. Segment AD is 16, segment AE is 24, segment EC is 36, and segment FC is 27.


Which statement can be proved true using the given theorem?
Segment BD = 32
Segment BD = 36
Segment BF = 15
Segment BF = 18

Respuesta :

Answer:

  • Segment BF = 18

Step-by-step explanation:

We have triangle ABC with:

  • Point D is on side AB
  • Point E is on side AC
  • Point F is on side BC
  • AD = 16,  AE = 24, EC = 36, FC = 27

Proportions would be:

  • BD/AD = EC/AE ⇒ BD = AD*AC/AE ⇒ BD = 16*36/24 = 24
  • BF/FC = AE/EC ⇒ BF = FC*AE/EC ⇒ BF = 27*24/36 = 18

Correct choice is D

The answer is D: Segment BF = 18

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