Question

Factor the expression
49x^5 - 63x^3

Answer 1

Answer:

7x³(7x² - 9)

Step-by-step explanation:

Hope this helps!

Answer 2

Answer:

$7x^3(7x^2-9 )$

Step-by-step explanation:

To factor, you have to find the GCF of 49 and 63 and the GCF of $x^{5}$ and $x^3$

Factor 49: 1,7, and 49

Factor 63: 1, 3, 7, 9, 21, 63

Factor $x^{5}$: $x*x*x*x*x$

Factor $x^3$: $x*x*x$

So the GCF of 49 and 63 is 7

The GCF of $x^{5}$ and $x^{3}$ is $x^3$

We multiply 7 by $x^{3}$ to get $7x^3$

So now we start to factor out the GCF of $49x^5-63x^3$

$7x^3(\frac{49x^5}{7x^3}+ \frac{63x^3}{7x^3} )$

$\frac{49}{7} =7\\x^5-x^3=x^2$

$\frac{63}{7} =9\\x^3-x^3=x^0$ because $x^{0}$ can't be written as an exponent we don't write $9x^0$

When we factor we get $7x^3(7x^2-9 )$