Write an equation in slope-intercept form for the line perpendicular to y=2x−3 that passes
through the point (−3,−3).

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Answer:

y = -1/2x - 9/2

Step-by-step explanation:

If two lines are perpendicular to each other, they have opposite slopes.

The first line is y = 2x - 3. Its slope is 2. A line perpendicular to this one will have a slope of -1/2.

Plug this value (-1/2) into your standard point-slope equation of y = mx + b.

y = -1/2x + b

To find b, we want to plug in a value that we know is on this line: in this case, it is (-3, -3). Plug in the x and y values into the x and y of the standard equation.

-3 = -1/2(-3) + b

To find b, multiply the slope and the input of x (-3)

-3 = 3/2 + b

Now, subtract 3/2 from both sides to isolate b.

-3 - 3/2 = b

-6/2 - 3/2 = b

-9/2 = b

Plug this into your standard equation.

y = -1/2x - 9/2

This equation is perpendicular to your given equation (y = 2x - 3) and contains point (-3, -3)

Hope this helps!

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