Quite an aggressive question but I gotchu
When you’re finding a line perpendicular to a given equation, the slope will be the negative reciprocal: that is, if “m” is representing the current slope and “m’” represents the new slope, then m’ = -1/m. Therefore, the new slope will be -1/(-3) or simply 1/3. As for the point, we must substitute in the values with our current slope. If x0 is the x-intercept (what x equals when y=0), then we have y=(1/3)x + x0. If y=5 and x=8 as it is with the given point, we have 5=(1/3)(8) + x0. Solving this we get x0=(7/3)… then the equation of the first problem is y=(1/3)x + (7/3)
As for the second problem, the slope is the same (-3). Just have y=-3x+x0, and subbing in the point we have 5=-3(8)+x0. For this to be true, x0 must be 29 (found by solving the equation). Therefore the answer to the second problem is y=-3x+29.
Hope this helps!
