Using a paired t test, the Pvalue is less than the value of the test statistic. Hence, we reject the Null hypothesis.
The hypothesis :
[tex]H_{0} = μ_{d} ≤ 0 [/tex]
[tex]H_{1} = μ_{d} > 0 [/tex]
The test statistic can be calculated thus :
Test statistic = [tex] \frac{μ_{d}}{\frac{S_{d}}{\sqrt{n}}} [/tex]
Using a calculator :
Inputting the values into the formula :
Test statistic = [tex] \frac{23}{\frac{38.86}{\sqrt{12}}} [/tex]
Test statistic = [tex] \frac{23}{11.217} = 2.05 [/tex]
Calculating the P-value :
Pvalue = 0.03 (Pvalue calculator)
Since the Pvalue < α ; We reject the Null hypothesis.
Learn more : https://brainly.com/question/25651592