Respuesta :
- Al ⇒ Al³⁺ is an oxidation and 3 electrons on the right side are needed.
- Cu²⁺ ⇒ Cu is a reduction and 2 electrons on the left side are needed.
- 2 F⁻ ⇒ F₂ is an oxidation and 2 electrons on the right side are needed.
In a redox reaction, we can identify 2 kinds of half-reactions:
- Oxidation: the oxidation number increases.
- Reduction: the oxidation number decreases.
Let's consider the following half-reactions.
- Al ⇒ Al³⁺
This is an oxidation because the oxidation number increases from 0 to 3+. To balance it, we need 3 electrons on the right side.
- Cu²⁺ ⇒ Cu
This is a reduction because the oxidation number decreases from 2+ to 0. To balance it, we need 2 electrons on the right side.
- 2 F⁻ ⇒ F₂
This is an oxidation because the oxidation number increases from -1 to 0. To balance it, we need 2 electrons on the right side.
- Al ⇒ Al³⁺ is an oxidation and 3 electrons on the right side are needed.
- Cu²⁺ ⇒ Cu is a reduction and 2 electrons on the left side are needed.
- 2 F⁻ ⇒ F₂ is an oxidation and 2 electrons on the right side are needed.
Learn more: https://brainly.com/question/2671074
Identify whether each change represents an oxidation or reduction. then determine how many electrons were involved and which side of the reaction they should appear on in the half-reaction.
Al ⇒ Al³⁺
Cu²⁺ ⇒ Cu
2 F⁻ ⇒ F₂
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