Answer:
A
Step-by-step explanation:
The minimum value is the y- coordinate of the vertex
Given a parabola in standard form
y = ax² + bx + c ( a ≠ 0 )
Then the x- coordinate of the vertex is
x = - [tex]\frac{b}{2a}[/tex]
y = 3x² - 12x + 10 ← is in standard form
with a = 3 and b = - 12 , then
x = - [tex]\frac{-12}{6}[/tex] = 2
Substitute x = 2 into the function for corresponding y- coordinate
y = 3(2)² - 12(2) + 10 = 3(4) - 24 + 10 = 12 - 24 + 10 = - 2
Then minimum value of the function is - 2
