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Calculate the mass of 6.9 moles of nitrous acid (HNO2). Explain the process or show your work by including all values used to determine the answer.

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Answer:

324.4 grams

Explanation:

47.013 g/mol is the molar mass of the nitrous acid.

Therefore with weight, nitrous acid is equal to 47.013 grams.

This value can be utilized to determine the mass of 6.9 moles within the same compound.

Since a single mole = 47.013 grams, we simply multiply:

6.9 x 47.013 = 324.4

The mass of the given nitrous acid contained in 6.9 moles is 324.3 g.

The molecular mass of the given nitrous acid is calculated as follows;

HNO₂ = (1) + (14) + (16 x 2)

M  = 47 g/mol

The mass of the given nitrous acid contained in 6.9 moles of the acid is calculated as follows;

m = nM

where;

  • n is the number of moles of the acid
  • M is the molecular mass

m = 6.9 x 47

m = 324.3 g

Thus, the mass of the given nitrous acid contained in 6.9 moles is 324.3 g.

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