The magnitude of centripetal acceleration of the both bodies is 1 m/s^2.
The centripetal acceleration is given by the relation;
a = v^2/r
v = velocity
r = radius of the circular
We have the following information;
v = 1.0 m/s
r = 1.0 m
In each case, the magnitude of centripetal acceleration is;
a = 1^2/1 = 1 m/s^2
Learn more: https://brainly.com/question/11324711