Question

a(b-c)+b(c-a)+c(a-b)
​

Answer 1

$\sf \pink{a(b-c)+b(c-a)+c(a-b) }$

$\sf =ab -ac +bc -ba +ca -cb$

$\sf =ab -ac +bc -ab +ac -bc$

$\sf = \cancel{ab} - \cancel{ac} + \cancel{bc} - \cancel{ab} + \cancel{ac} - \cancel{bc}$

$\sf \pink{=0}$