Answer:
N=400×e^(0.45t)
4.58×10^8 at 2pm next day
104 for 3 hours before
(Such a fast rate...wondering if there were more 0's behind that decimal)
Step-by-step explanation:
Let's assume 7am is the intial. So at t=0, we have N_0=400.
This means the equation is N=400×e^(0.45t).
2pm next day is 7+24 hours later. So replace t with 31 giving us N=400×e^(0.45×31)=4.58 ×10^8 approximately.
3 hours before the expression began at at t=-3:
N=400×e^(0.45×-3)=104 approximately.
