Answer:
In order: (75; 55; 55; 40; 140; 40; 70; 65; 115)
Step-by-step explanation:
Ok, let's get rid of a few angles. the pairs 2 and 3; 4and 6, and 8 and 65°C are each congruent to each other. So we found one angle ([tex]\angle 8 = 65°[/tex]) Eight to go.
On the leftmost triangle, 125 is an external angle and it's equal to the sum of the internal angles not sharing the vertex, in this case 1 and 50°. Follows that [tex]\angle1 = 125-50 = 75°[/tex]
At this point we can find 2(and thus 3) by subtraction: they both are supplementary to 125, so [tex]\angle2 = \angle3=55°[/tex]
Angle 4 (and 6) are easy to find, since the sum of the internal angle of a triangle is 180: [tex]55+85+x= 180 \rightarrow x = 40°[/tex].
Angle 5 has to be supplementary to 4 (or 6, your choice). so it's 140°
Angle 7 we find considering that we know 6 and 8, again internal angles sum to 180: [tex]40+y+65=180 \rightarrow y=75[/tex]
Finally angle 9 has to be supplementary to 65°, so it's 115°.
