Step-by-step explanation:
Let the distance points A = (5,-2) and B = (-2,12)
Distance between AB = √[(x2-x1)²+(y2-y1)²]
Here, x1 = 5, y1 = -2
x2 = -2 , y2 = 12
Now,
Put all the values in distance formulae:
AB = √[(-2-5)²+{12-(-2)}²]
= √[(-7)²+(14)²]
= √[(-7*-7)+(14*14)]
= √[49 + 196]
= √[245] = 15.65 Units. Approximately.
Answer:- Hence, the distance between two points A(5, -2) and B(-2, 12) is 15.65 Units approximately.
