Question

8. John has to hit a bottle with a ball to win a prize. He throws a 0.4 kg ball with a velocity of 18 m/s. It hits a 0.2 kg bottle, and the bottle flies forward at 25 m/s. How fast is the ball traveling after hitting the bottle?

Answer 1

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Answer 2

Answer: The velocity of the ball the ball after collision is 5.5 m/s.

Explanation:

John hitting the bottle which is at rest means this is an Elastic collision.

Mass of the ball= $M_1=0.4 kg$

Velocity of ball before collision = $U_1=18m/s$

Velocity of ball after collision =$V_1$

Mass of the bottle= $M_2=0.2 kg$

Velocity of bottle before collision = $U_2=0 m/s$(bottle is at at rest)

Velocity of bottle after collision =$V_2=25 m/s$

$M_1V_1+M_2V_2=M_1U_1+M_2U_2$

$V_1=\frac{(0.4 kg\times 18 m/s+0.2 kg\times 0m/s)-0.2 kg\times 25m/s}{0.4}$

$V_1=5.5 m/s$

The velocity of the ball the ball after collision is 5.5 m/s.