Question

What is the product of 2p + q and –3q – 6p + 1?
–12p2 – 6pq – 4p – 3q + 1
–12p2– 12pq + 2p – 3q2 + q
–9p2q2 + 12pq – 2p + q
12p2 + 12pq +2p + 3q2 + q

Answer 1

Answer:  Second option is correct.

Step-by-step explanation:

Since we have given that

$(2p+q)\ and\ (-3q-6p+1)$

We need to product the two polynomials .

Here it is :

$(2p+q)(-3q-6p+1)\\\\=2p(-3q-6p+1)+q(-3q-6p+1)\\\\=-6pq-12p^2+2p-3q^2-6pq+q\\\\=-12p^2-3q^2+2p+q-12pq$

Hence, Second option is correct.

Answer 2

The product of the 2p + q and –3q – 6p + 1 is $\rm -12p^2-12pq+2p-3q^2+q$.

Given

The given terms are;

2p + q and –3q – 6p + 1

How to calculate the product of given terms?

To find a product, you'll need to multiply at least two numbers together following all the steps given below.

The product of the terms is;

$\rm = (2p+q) \times (-3q-6p+1)\\\\= 2p\times (-3q-6p+1) + q\times (-3q-6p+1)\\\\= 2p\times (-3q) +2p\times (-6p)+2p\times (1) + q\times (-3q) + q\times(-6p) +q\times (1)\\\\=-6pq-12p^2+2p-3q^2-6pq+q\\\\= -12p^2-12pq+2p-3q^2+q$

Hence, the product of the 2p + q and –3q – 6p + 1 is $\rm -12p^2-12pq+2p-3q^2+q$.

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https://brainly.com/question/4281741