Answer:
The tree is 6.19 metres tall
Step-by-step explanation:
Tan 45° = H/10
H = 10 (Tan45°)... let this be the first equation
Let the distance between Q and P be X
Tan 30° = H/(10 + X)
H = Tan30° (10 + X)...let this be equation 2
But H = H,
so 10 (Tan45°) = Tan30° (10 + X)
10 (1) = 0.5774 (10 + X)
10 = 5.774 + 0.5774X
(10 - 5.774) = 0.5774X
4.226 = 0.5774X
X = 0.73
So H will be :
H = Tan30° (10 + X)
H = 0.5773 (10 + 0.73)
H = 6.19m