Respuesta :
Keywords
quadratic equation, discriminant, complex roots, real roots
we know that
The formula to calculate the roots of the quadratic equation of the form [tex]ax^{2} +bx+c=0[/tex] is equal to
[tex]x=\frac{-b(+/-)\sqrt{b^{2}-4ac}}{2a}[/tex]
where
The discriminant of the quadratic equation is equal to
[tex]b^{2}-4ac[/tex]
if [tex](b^{2}-4ac)> 0[/tex] ----> the quadratic equation has two real roots
if [tex](b^{2}-4ac)=0[/tex] ----> the quadratic equation has one real root
if [tex](b^{2}-4ac)< 0[/tex] ----> the quadratic equation has two complex roots
in this problem we have that
the discriminant is equal to [tex]-8[/tex]
so
the quadratic equation has two complex roots
therefore
the answer is the option A
There are two complex roots