Question

Here is our problem
Here is a system of linear equations
Equation 1: y= x-2
Equation 2: y =-2x+13
The following system of equations was obtained by adding a multiple of Equation 2 to Equation 1.
Equation 3: y= x-2
Equation 4: 4y= 5x +37

Answer 1

Answer:

 x =  5   and y = 3     solution is (5, 3)

Step-by-step explanation:

y = x - 2              multiply each term by 2

y = -2x + 13        Do not change

2y = 2x - 4

y = -2x + 13

3y =       9

  y = 9/3

  y = 3

y = x - 2      Substitute y = 3 and solve for x

3 = x - 2

5 = x