Respuesta :
The concentration of NaOH is 25.00% by mass, it means that 25.00% of the mass of the solution is of NaOH. Hence:
[tex]m_{NaOH}=25.00\%\times m_{solution}\Longrightarrow m_{NaOH}=\dfrac{25}{100}\times 0.250~g\iff\\\\\boxed{m_{NaOH}=0.0625~g}[/tex]
[tex]m_{NaOH}=25.00\%\times m_{solution}\Longrightarrow m_{NaOH}=\dfrac{25}{100}\times 0.250~g\iff\\\\\boxed{m_{NaOH}=0.0625~g}[/tex]
Answer : The mass of NaOH present in the solution is, 0.0625 grams
Explanation : Given,
Mass % = 25 %
Mass of solution = 0.250 g
Formula used :
[tex]Mass\%=\frac{\text{Mass of}NaOH}{\text{Mass of solution}}\times 100[/tex]
Now put all the given values in this formula, we get the mass of NaOH.
[tex]25=\frac{\text{Mass of}NaOH}{0.250g}\times 100[/tex]
[tex]\text{Mass of}NaOH=0.0625g[/tex]
Therefore, the mass of NaOH present in the solution is, 0.0625 grams