Question

A log rolls down a hill. When first measured the speed of the log in 1.3 m/s, after 4 seconds its speed is 3.2 m/s. If the log has a mass of 220 kg, what is the
force?
N (Round to 2 significant figures)

Answer 1

The force acting on the log as it rolls down a hill is equal to 104.5 Newton.

Given the following data:

• Initial velocity = 1.3 m/s

• Time = 4 seconds

• Final speed = 3.2 m/s

• Mass = 220 kg

To determine the force acting on the log:

First of all, we would calculate the acceleration of the log by using this formula:

$Acceleration = \frac{V\;-\;U}{t} \\\\Acceleration = \frac{3.2\;-\;1.3}{4} \\\\Acceleration =\frac{1.9}{4}$

Acceleration = 0.475 $m/s^2$

Now, we can solve for the force by applying Newton's Second Law of Motion:

$Force = mass \times acceleration$

$Force = 220 \times 0.475$

Force = 104.5 Newton

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