The net torque about point O for the two forces applied as in the figure below is 17.4Nm
Find the diagram to the question attached
Given the following parameters
F1 = 7.80N
F2=11.0N
Taking the force along the vertical;
τ₂ = 7.80sin30(2.0)
τ₂ = 15.6Nm
For the other force along the vertical;
τ₁ = 11.0 * 3
τ₁ = 33Nm
Net torque is expressed as = 33Nm - 15.6Nm
Net torque = 17.4Nm
Hence the net torque about point O for the two forces applied as in the figure below is 17.4Nm
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