ncurren23 ncurren23

02-11-2021
Mathematics

contestada

I need help finding how this would work with numerical relationships x^3-3x^2+3xy^2-y^3=(x-y)^3

Thx in advance

Respuesta :

Аноним Аноним

02-11-2021

Answer:

y=mx+b

Step-by-step explanation:

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