Answer:
x = - 3
Step-by-step explanation:
y = 5 + [tex]\frac{1}{x+3}[/tex]
= [tex]\frac{5(x+3))+1}{x+3}[/tex] = [tex]\frac{5x+16}{x+3}[/tex]
The denominator of y cannot be zero as this would make y undefined
Equating the denominator to zero and solving gives the value that x cannot be and if the numerator is non- zero for this value then it is a vertical asymptote.
x + 3 = 0 ⇒ x = - 3
The vertical asymptote is x = - 3
