Question

6.
Write an equation for the line that is parallel to the given line and that passes through the given point.

y = –5x + 3; (–6, 3)

A. y = –5x – 27

B. y = 5x – 9

C. y = –5x + 9

D. y = –5x + 27

Answer 1

Answer:

A. y = –5x – 27

Step-by-step explanation:

Find the slope of the original line and use the point-slope formula  y − y 1 = m ( x − x 1 )  to find the line parallel to  y = − 5 x + 3 .

y = − 5 x − 27                           PARALLEL

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Find the negative reciprocal of the slope of the original line and use the point-slope formula  y − y 1 = m ( x − x 1 )  to find the line perpendicular to  y = − 5 x + 3 .

y = 1 /5 x + 21 /5                    PERPENDICULAR