Using the frequency table, it is found that:
a) 99.2% of the group of eggs were less than 24.75 mm long.
b) 0.471 = 47.1% probability that one of the eggs selected at random was at least 21.75 mm long but less than 24.75 mm long.
The frequency table gives the percentage of cuckoo bird eggs with the associated lengths.
Item a:
Thus, 100 - 0.8 = 99.2% were less than 24.75 mm long.
Item b:
In total:
[tex]37.9 + 28.5 + 10.7 = 47.1[/tex]
47.1% of the eggs are in these lengths, thus, 0.471 = 47.1% probability that one of the eggs selected at random was at least 21.75 mm long but less than 24.75 mm long.
A similar problem is given at https://brainly.com/question/24141790