Question

The bases on a softball diamond are 60 feet apart. How far is it from home plate to second base?

Answer 1

So use the pathagoris theorem. a^2+b^2=c^2 60 x 60 = 3600 so 3600 + 3600 = 72000 the square root of 7200 is 84.85 The distance between the home plate and the 2nd vase is 84.85 feet :)

Answer 2

Answer:

84.85 feet apart

Step-by-step explanation:

a² + b² = c²

60² + 60² = c²

3600 + 3600 = 7200

$\sqrt{7200}$

84.85 feet

:)