Question

A ball rolls down a ramp for 5 seconds. It accelerated 3m/s2 until it reached 28 m/s. What was the ball’s initial velocity? (select the correct equation)

Answer 1

Answer:

Option 4 is correct ,

Explanation:

By the question,

Time (t) = 5 sec

accelation (a) = 3m/s^2

final velocity (Vf) = 28m/s

we know that ,

$a = \frac{vf - vi}{t}$

so, doing cross multiplication , we get:-

$vf - vi = a \times t \\ vi = vf - a \times t \\ vi = 28 - (3 \times 5)$