Using the probability concept, it is found that there is a [tex]\frac{4}{9}[/tex] probability that the second chosen is also a boy.
In this problem, supposing that the first person chosen is a boy:
Hence:
[tex]p = \frac{12}{27} = \frac{4}{9}[/tex]
There is a [tex]\frac{4}{9}[/tex] probability that the second chosen is also a boy.
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