Respuesta :

is it factorisatiom or solving equation?

Step-by-step explanation:

2m² + 2m - 12 divide the equation by 2

then: m² + m - 6

factorise: (m + 3)(m - 2)

solve m + 3 =0 or m - 2 =0

m= -3 or m = 2

Answer:

[tex]\boxed{\sf m=2,\:m=-3}[/tex]

Step-by-step explanation:

[tex]\sf 2m^2+ 2m - 12 = 0[/tex]

We can solve the problem by the quadratic equation:

[tex]\boxed{\sf x=\cfrac{-b\pm \sqrt{b^2-4ac}}{2a}}[/tex]

[tex]\sf a=2,\:b=2,\:c=-12[/tex]

[tex]\sf m=\cfrac{-2\pm \sqrt{2^2-4\times \:2\left(-12\right)}}{2\times \:2}[/tex]

lot's solve [tex]\sf \sqrt{2^2-4\cdot \:2\left(-12\right)}[/tex]

Multiply 4 * 2* 12= 96

→ [tex]\sf \sqrt{2^2+96}[/tex]

→ [tex]\sf \sqrt{4+96}[/tex]

Add 4 + 96= 100

→ [tex]\sf \sqrt{100}[/tex]

→ [tex]\sf \sqrt{10^2}[/tex]

→ [tex]\sf 10[/tex]

________________

[tex]\sf m=\cfrac{-2\pm \:10}{2\times \:2}[/tex]

Separate solutions:

[tex]\sf m_1=\cfrac{-2+10}{2\times \:2}[/tex]

Add/Subtract then Multiply:

→ [tex]\sf \cfrac{8}{2\times \:2}[/tex]

Divide:

→ [tex]\sf \cfrac{8}{4}[/tex]

→ [tex]\boxed{\sf 2}[/tex]

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Add/Subtract then Multiply:

[tex]\sf m_2=\cfrac{-2-10}{2\times \:2}[/tex]

→ Divide:

→ [tex]\sf -\cfrac{12}{4}[/tex]

→ [tex]\boxed {\sf -3}[/tex]

Solutions:

[tex]\sf m=2,\:m=-3[/tex]

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you can learn more about quadratic equations here → https://brainly.com/question/25312497

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