Answer:
Step-by-step explanation:
[tex]e^{.09*10}=(1+\frac{x}{12})^{(12*10)}\\e^{.9}=(1+\frac{x}{12})^{120}\\e^{\frac{.9}{120}}=1+\frac{x}{12}\\12(e^{\frac{.9}{120}}-1)[/tex]
^ that's the exact answer. Put that into a calculator and get .090338345334
which rounds to 9.03%
