Question

You just bought a new briefcase and need to pick a four digit combination out of 10 possible numbers for the lock. If order does matter how many possible lock combinations can you choose from?

Answer 1

Answer:

5040

Step-by-step explanation:

for nPr use $\frac{n!}{(n-r)!}$

so for

10P4 do $\frac{10!}{(10-4)!}=\frac{10!}{6!}=5040$