Question

Find f(b-2) if f(x) = x^2-6x+1

Answer 1

$▪▪▪▪▪▪▪▪▪▪▪▪▪  {\huge\mathfrak{Answer}}▪▪▪▪▪▪▪▪▪▪▪▪▪▪$

The equivalent expression is ~

• $f(b - 2) = {b}^{2} - 10b + 17$

$\large \boxed{ \mathfrak{Step\:\: By\:\:Step\:\:Explanation}}$

Let's evaluate f(b - 2) ~

• $f(x) = {x}^{2} - 6x + 1$

• $f(b - 2) = (b - 2) {}^{2} -6 (b - 2) + 1$

• $\mathcal{ {f(b - 2) = {b}^{2} + 2 {}^{2} - (2 \times b \times 2) - 6b + 12}}$

• $f(b - 2) = {b}^{2} + 4 - 4b - 6b + 12 + 1$

• $f(b - 2) = {b}^{2} - 10b + 17$

Answer 2

Answer:

b^2-10b+ 17

Step-by-step explanation:

f(b-2) = (b-2)^2-6(b-2)+ 1

= b^2 + 4 - 4b -6b + 12 +1

=b^2-10b+ 17