Question

Calculate the force of gravity between a comet with a mass of 500kg and a small asteroid with a mass of 20kg that is separated by only 2.12 m.

Answer 1

$▪▪▪▪▪▪▪▪▪▪▪▪▪  {\huge\mathfrak{Answer}}▪▪▪▪▪▪▪▪▪▪▪▪▪▪$

The equivalent gravitational force is ~

• $F \approx1.48\times 10 {}^{ - 7} \: \: N$

$\large \boxed{ \mathfrak{Step\:\: By\:\:Step\:\:Explanation}}$

We know that ~

$\huge\boxed{\mathrm{F = \dfrac{ Gm_1m_2}{ r²}}}$

where,

• F = gravitational force

• $m_1$ = mass of 1st object = 500 kg

• $m_2$ = mass of 2nd object = 20kg

• G = gravitational constant = $6.674 × {10}^ {-11}$

• r = distance between the objects = 2.12 m

Let's calculate the force ~

• $F = \dfrac{6.674 \times 10 {}^{ - 11} \times 500 \times 20}{(2.12) {}^{2} }$

• $F = \dfrac{6.674 \times 10 {}^{ - 11} \times 10 {}^{4} }{4.4944}$

• $F = \dfrac{6.674}{4.4944} \times 10 {}^{ - 7}$

• $F =1.484 \times 10 {}^{ - 7} \: \: newtons$