Respuesta :

Some of the paper is not shown.

I'll do (26 - 32)

26.

92 days

The length of the astronomical seasons varies between 89 and 93 days, while the length of the meteorological seasons is less variable and is fixed at 90 days for winter in a non-leap year (91 days in a leap year), 92 days for spring and summer, and 91 days for autumn.

27. There are 21 cars, each 4m long, so 21x4m = 84 m gives the total length of the cars.

  • Then you have to work out the total length of the gaps between the cars, which is
  • 20x 1m, giving 20m.
  • (The number of gaps between the cars = number of cars -1, so 21-1=20, i.e., 20 gaps. If in doubt, always try these things with small numbers first. For example, if there were 2 cars, there would be 1 gap. If there were 3 cars, there would be 2 gaps, so there is always one less gap than the number of cars.)
  • The total length of the cars plus the total length of the gaps gives the length of the queue of 21 cars, so
  • 84m + 20m = 104m.

28.  

Cancel out all other squares.

Add A to each section to see how many spaces it could hypothetically take up.

3 each "row" of the square.

3 x 3 = 9

29.

Square A (all squares sides are congruent)

L = 2 W = 2

2 x 2 =4

SQUARE A = 2 (Area)

The large square is 3 blocks a row

so  add 2 + 2  + 2 which is 6

so 6 x 6 = 36

Area of large square = 36

Hint: Cross-sectional area is determined by squaring the radius and then multiplying by 3.14.

32

To find perimeter, add all the lengths and widths up of the square

so the length and width are 6.

So 6 + 6 = 12 + 12 = 24

p = 24

Otras preguntas

ACCESS MORE
EDU ACCESS
Universidad de Mexico