Answer:
2 m and 6.25 m for a and b respectively
Explanation:
Acceleration (a) = (2-0)/2 = 1 ms^-2 for first 2s
Distance = u*t + 0.5 *a*t^2
= 0 * 2 + 0.5 * 1 * 2^2
= 2 m
btn 2 and 4s
Acceleration a = (2.5-2)/2 = 0.25 ms^-2
Distance = u*t + 0.5 *a*t^2
=2*2+0.5 *0.25*2^2
= 4.5 m
btn 4 and 5s
Acceleration a = (1-2.5)/1 = -1.5 ms^-2
Distance = u*t + 0.5 *a*t^2
= 2.5*1 + 0.5 * -1.5*1^2
= 1.75 m
Total distance Btn 2 and 5s = 4.5 + 1.75 m
= 6.25 m
