Answer:
a)2 b)5
Explanation:
u will need the area under the curve
a) V= 2m/s
t=2s
d=?
we know that
v=d/t
2=d/2
d=2×2
d=4m
b) initial velocity(u)= 2m/s
final velocity(v)= 1 m/s
time(t)= 3s
distance(s)=?
s = average velocity × time
s = (u+v/2)×t
s =( 2+1/2)×3
s = (3/2)×3
s= 4.5m
