Question

Chlorine has two naturally occurring isotopes: chlorine-35 and chlorine-37. The mass of an atom of chlorine-35 is 5.807 x 10-23 g and that of an atom of chlorine-37 is 6.139 x 10-23 g. In a typical natural sample of chlorine, 75.77% of the sample is chlorine-35 and 24.23% is chlorine-37. (a) Calculate the mass of 35Cl and 37Cl in atomic mass unit (amu). (b) Calculate the relative atomic mass of chlorine. (c) What the molar mass of the sample of chlorine

Answer 1

The relative atomic mass of chlorine is 35.5 and its molecular mass is 71 g/mol.

Given that;

1amu = 1.66 x 10-24 grams

To find the mass of chlorine-35 in amu = 5.807 x 10-23 g × 1 amu/ 1.66 x 10-24 grams

= 34.98 amu

To find the mass of chlorine-37 in amu;  6.139 x 10-23 g × 1 amu/ 1.66 x 10-24 grams

= 36.98 amu

To find the relative atomic mass of chlorine;

RAM = (0.7577 × 34.98 amu) + (0.2423 × 36.98 amu)

RAM = 26.50 + 8.96

RAM = 35.5

Since chlorine is a diatomic substance that exists as Cl2, the molar mass of chlorine is 2(35.5) = 71 g/mol

Learn more: https://brainly.com/question/14283892